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# differentiating the clamping growth curve

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## differentiating the clamping growth curve

If a guy’s clamped girth is X(1) and his unclamped girth is Y(1), what do you suppose is the average time (T ave) required for Y(1)=X(2) (his new unclamped girth)?

42

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Originally Posted by jqsderrida
If a guy’s clamped girth is X(1) and his unclamped girth is Y(1), what do you suppose is the average time (T ave) required for Y(1)=X(2) (his new unclamped girth)?

Infinite, I hope. If Y(1) [initial unclamped] =X(2) [later clamped] then the clamped girth would have decreased, assuming Y(1) < X(1).

Did I read somewhere that you we’re getting a PhD in math?

Use this formula: T ave = sqrt(x2+y2)[a/sqrt(x2+y2) + bi/sqrt(x2+y2)]

Originally Posted by drilla9
42

42? No man, that’s the meaning of Life.

Originally Posted by JeanJeudi
42? No man, that’s the meaning of Life.

Ah… hmm, so… 43?

Going for 6 inches of girth, wish me luck.

69?

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Originally Posted by hbgreek
Infinite, I hope. If Y(1) [initial unclamped] =X(2) [later clamped] then the clamped girth would have decreased, assuming Y(1) < X(1).

Did I read somewhere that you we’re getting a PhD in math?

This is essentially a joke, however, if T ave is infinite then clamping is not efficacious whatsoever as X(2) is defined as future unclamped girth. 69 sounds like the right answer to me. To answer your last question: yes, I’m getting a PhD in math… what can I say? - to each his own.

Wtf!?!?!?

Haven’t you people watched Jim Carey’s new movie? The number 23? EVERYTHING revolves around the number 23 ;)

Past: 5-5.5" BPEL x 4.5" GIRTH

Present: 7.55" BPEL x 5.55" GIRTH (1 year progress)

Future: 8-9" BPEL x 6" GIRTH

Sorry, what was the question again?….

LWH

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Originally Posted by jqsderrida

Clamped girth is X(1)

Originally Posted by jqsderrida

X(2) is defined as future unclamped girth.

I know it’s a joke. Just taking a jab at your mistake.

Good eye. Obviously it should read X(1)=Y(2).

I guess that’s what peer-reviewing is good for :)

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