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Weight/Math Question - ???


Originally Posted by pudendum
I apologize for my overly technical and verbose explanation regarding blood pressures in the cavernosa at full erection. The point I wanted to get across was that after the cavernosa and spongiosum fill and reach a pressure equal to the blood pressure throughout the rest of the body, no more blood can enter as ticktickticker said. But part of the reflex that causes erections cause the Ischiocavernosus muscles to contract (located deep to the scrotum where the cavernosa anchor to the pelvic bone; they override the cavernosa at this anchoring point). This forces blood up into the rest of the cavernosa causing the erection to get firmer and stand out. This generates a pressure within the cavernosa 80 - 90% above the blood pressure in the rest of the body.

I should have said it this way in my prior post. I will in the future.

Thank you pudendum for that clarification.

Later - ttt

Originally Posted by pudendum
9.8 Newtons = 1 kg. 1 kg = 2.2 lbs. So 1 Newton of force is equal to 0.22 lbs of force.
51.7 mmHg (millimeters mercury pressure) = 1 psi
1 psi = 6893 N/meters squared

I attempted to get the original manuscript from my medical library electronic resource, but unfortunately their subscription starts in 1995. An abstract is a very sparse presentation of data and has a very limited description of methods; in this case particularly regarding the harvesting of the TA from their “volunteers.” Thunder is right. The donors were dead. TA is a living tissue, not just a plain fibroelastic layer. When tissue dies, its compliance changes. It generally decreases; that is it gets stiffer. With all this in mind I will tell you what I think. Be aware that their interest is in cavernosa compliance with expansion, not stretch (which are probably different).

Thanks for every ones’ replies. I never supposed this article to be a tell-all of tunica deformation. However, I do think it has significance in helping us get somewhat of a handle on the tunica’s tensile strength. Yes, it is obvious that the methods involved internal expansion as opposed to mechanical stretch. And, while I agree that the tissue composition is likely to undergo some postmortem changes I don’t it is reasonable to write off the entire outcome as not applicable to living tissue. I think we can logically conclude that the intelligence of those conducting this experiment would be sufficient to make the same analysis. If the deceased tissue was dramatically different than living it’s highly unlikely they would have benefited from or conducted the tests in the first place. But, the fact that they did tells us they were expecting to gather some useful information that was applicable to living humans.

While this data may not be “dead on” when concerning living tissue or entirely useful where mechanical stretch is involved, it very well may be as far as pumping, clamping or jelqing is concerned. At the very least it’s a good starting point for learning more.

Let me tell you the secret that has led me to my goal: my strength lies solely in my tenacity.

Louis Pasteur

I didn’t bother to read the rest of the thread, so I don’t know if anyone has answered this already, but this is what I would do.

It’s giving the tensile strength of the tunica, this means the strength of the tunica along the length of the penis. The results are given in pressures, which you can then convert into forces and then into weights. I’m going to use metric because it’s much easier.

So let’s take the tensile strength as 10^5 N/m^2, or 100 000 N/m^2. To get the force you would need to deform the tunica you need to know the area this pressure is acting on… hence the cross-sectional area of the tunica (cross-sectional meaning if you’re looking straight at your penis head on and you cut it in half, the cross-section of the penis is what you’d see). This is going to be tough since I doubt anyone knows exactly how thick the tunica is. If anyone is confused there’s a picture below of what I mean. Just to do an example calculation I’m going to assume randomly that my tunica is 2 mm, or 0.002 m thick. Now to get the area of the dark pink circle (look at picture), I get the area of the cross section of my entire cock (dark pink and light pink section… pi*r^2), here r is the radius and is 0.0243 m, so the area is 0.00185 m^2. To get the area of just the dark pink section you need to subtract the area of the light pink section. The diameter of the light pink section will be 2 mm less than that of the whole cock since the tunica is 2 mm thick… and thus the radius will be only 1 mm less than that of the whole cock. I won’t put in any calculations here, but for the area of my 2 mm thick tunica I get 0.00029 m^2.

Ok… so now to get the force acting on the tunica you multiply the area by the pressure, so 100 000*0.00029… and we get 29 N. To convert Newtons to kg’s you just divide by the gravitational acceleration, which is 9.81 m/s^2, and we get 2.96 kg. Obviously this isn’t right, probably because my tunica estimate is wrong. Do you understand what I did though?

Ok, I don’t see an attachment option for my picture. How can I attach it?

Mick-Your calculations to achieve cross-sectional area are sound. I’m not sure I agree with the values you used for your calculations. However, application of the article authors values to your calculation is questionable. The authors of the study (of which we only have the abstract) appear to have used tunica segments for their studies that were cross-sectional and not longitudinal and stretched them in a cross-sectional direction. Though the arrangement of the fibers is not uniform (basically rather random), my understanding is the predominant arrangement is circumferential and not longitudinal. The tunic is like a balloon; it stretches nicely when empty, but shortens and expands when full. This is why BPSFL generally is greater than BPEL. In addition, for an accurate assessment of the optimal tunica stretch to achieve plastic deformation is a compilation of the many cross-sectional areas down the entire length of the exposed penis. Therefore I believe your calculations my not hold.

I plan on getting the full article this week and when I do, I will email to anyone who is interested.

Originally Posted by Mick

Ok, I don’t see an attachment option for my picture. How can I attach it?

When you compose a new post (using the “post reply” button at the bottom of the thread) or quote from someone else’s post, or create a new thread there is a section below the text entry section called “Attach Files.” Section names are in the column to the left of the text entry area, which is called “Message.” Click the button labeled “Manage Attachments” and a second, smaller window will open allowing you to browse your computer for a file and upload it. A moderator has to approve your attachment before it will appear in your post. Since your ten minute editing time is up for your previous post, you’ll have to create a new one to attach your image. There are file type and size limitations. If your attachment doesn’t meet them it will not be put in the moderation queue and you will not receive any notice that it didn’t go through.


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