Originally posted by memento
Exactly there are 2 cords. So imagine the penis as 10 cords, sharing the tension, then break one cord under stress what happens to the tension in the remaining cords.
As I said:
Originally posted by Nedd
The tension in any [cross sectional] section of penis is the same. If part of the load bearing structure in said section fails, that load needs to be taken up by some other (part of a) structure in that section.
Ten cords sharing 10N means each cord ideally supports 1N. If one cord breaks, then nine cords sharing 10N means each cord ideally supports 10/9 = 1.11N.